4^x=(1/2)^x2-x

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Solution for 4^x=(1/2)^x2-x equation: 



4^x=(1/2)^x2-x

We move all terms to the left:

4^x-((1/2)^x2-x)=0



Domain of the equation: 2)^x2-x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4^x-((+1/2)^x2-x)=0

We multiply all the terms by the denominator


4^x*2)^x2-x)-((+1=0

Wy multiply elements

8x^2+1=0

a = 8; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·8·1
Δ = -32
Delta is less than zero, so there is no solution for the equation

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